which point lies on a circle with a radius of 5 units and center at P(6,1)?a. Q(1, 11)b. R(2, 4)c. S(4, -4)d. T(9, -2)

Given the center coordinates [tex] (h,k) [/tex] and the radius [tex] r [/tex], the equation of the circle is[tex] (x-h)^2 + (y-k)^2 = r^2 [/tex]So, the equation of your circle is[tex] (x-6)^2 + (y-1)^2 = 25 [/tex]We can plug the values from the options to see which one satisfy the equation:A) [tex] (1-6)^2 + (11-1)^2 = 25 +100 \neq 25[/tex]B) [tex] (2-6)^2 + (4-1)^2 = 16 +9 = 25[/tex]So, we already found the correct option. For the sake of completeness:C) [tex] (4-6)^2 + (-4-1)^2 = 4 +25 \neq 25[/tex]D) [tex] (9-6)^2 + (-2-1)^2 = 9 +9 \neq 25[/tex]