Q:

Laneka owns a cake shop. She is currently preparing cakes for two anniversary parties. The first cake has 3 small tiers and 1 medium tier and will serve a total of 100 guests. The second one has 3 small tiers and 2 medium tiers and will serve a total of 140 guests. 1.Represent the situation with a system of equations. 2. Solve the System of equations.

Accepted Solution

A:
Answer:The system of equations are [tex]\left \{ {{3s+m=100} \atop {3s+2m=140}} \right.[/tex].Step-by-step explanation:Let 's' represents the number of guest small tier can serve.Let 'm' represents the number of guest medium tier can serve.Now Given:For First cake:Number of small tiers = 3Number of medium tier = 1Total serving guest = 100 Now Total serving guest is equal to sum of Number of small tiers multiplied by the number of guest small tier can serve and Number of medium tiers multiplied by the number of guest medium tier can serve.Framing in equation form we get;[tex]3s+m=100[/tex]For Second cake:Number of small tiers = 3Number of medium tier = 2Total serving guest = 140 Now Total serving guest is equal to sum of Number of small tiers multiplied by the number of guest small tier can serve and Number of medium tiers multiplied by the number of guest medium tier can serve.Framing in equation form we get;[tex]3s+2m=140[/tex]Hence The system of equations are [tex]\left \{ {{3s+m=100} \atop {3s+2m=140}} \right.[/tex].