Given that sine= 21/29, what is the value of cos 0, for 0° <0<90°? A -square root of 20/29 B -20/29 C 20/29 D square root of 20/29
Accepted Solution
A:
Answer:Step-by-step explanation:sin=y/rcos=x/rsin=21/29cos=x/29x^2+y^2=r^2x^2+21^2=29^2x^2+441=841x=sqrt(841-441)x=20cos=20/29 Only | sin + | All Positive---------------------|------------------- only | Only cos + tan + |